The movement of a truck is described by the equation x1 = 270 + 12t, and the movement of a pedestrian

The movement of a truck is described by the equation x1 = 270 + 12t, and the movement of a pedestrian on the side of the same highway is described by the equation x2 = 1.5t. At what speeds and in what direction were they moving? When and where did they meet?

x1 (t) = 270 + 12 * t.

x2 (t) = 1.5 * t.

V1 -?

V2-?

tvs -?

xвс -?

The equation that describes uniform rectilinear motion has the form: x (t) = x0 + V * t, where x0 is the initial coordinate of the body, V is the speed of uniform rectilinear motion.

For the equation x1 (t) = 270 + 12 * t, initial coordinate x0 = 270, speed V1 = 12.

For the equation x2 (t) = 1.5 * t, the initial coordinate is x0 = 0, the speed of movement is V2 = 1.5.

The truck and the pedestrian walk in the direction of the OX axis.

When they meet, their coordinates are x1 (t) = x2 (t).

270 + 12 * t = 1.5 * t.

10.5 * t = -270.

t = – 25.7.

Since the time cannot be negative, the truck and the pedestrian will not meet. The pedestrian will not catch up with the truck.

Answer: the truck is moving at a speed of V1 = 12, a pedestrian at a speed of V2 = 1.5.