The movements of two aircraft flying in parallel courses are given by the equations x1 = 150t and x2 = 8400-250t.

The movements of two aircraft flying in parallel courses are given by the equations x1 = 150t and x2 = 8400-250t. What are the speeds of the aircraft and what is their direction? At what distance from each other at the initial moment of time are the aircraft? After what time will they meet?

x1 (t) = 150 * t.

x2 (t) = 8400 – 250 * t.

V1 (t) -?

V2 (t) -?

S -?

tvs-?

In rectilinear uniform motion, the coordinate of the body x (t) depends on time by the formula: x (t) = x0 + V * t, where x0 is the initial coordinate of the body, V is the speed of movement.

For dependence х1 (t) = 150 * t, initial coordinate х10 = 0, speed of movement V1 = 150.

The first plane moves uniformly in a straight line with a speed of V1 = 150.

For the dependence x2 (t) = 8400 – 250 * t, the initial coordinate is x20 = 8400, the speed of movement is V2 = 250. The second plane moves towards the first one at a speed of V2 = 250.

S = x20 – x01 = 8400.

150 * tvs = 8400 – 250 * tvs.

500 * tvs = 8400.

tvs = 8400/500 = 16.8 s.

Answer: V1 = 150, V2 = 250, S = 8400, tvs = 16.8 s.