# The NH3 gas was passed through sulfuric acid, 38 g of salt was formed, how much ammonia was in liters.

1. Let’s compose the equation for the reaction of the interaction of ammonia with sulfuric acid:

2 NH3 + H2SO4 = (NH4) 2SO4

According to the equation:

2 mol of ammonia enters into the reaction;
1 mole of ammonium sulfate is formed.
Let’s find the volume of NH3 by the formula:

V (NH3) = Vm * n = 22.4 L / mol * 2 mol = 44.8 L

Let’s find the mass of salt by the formula:

m ((NH4) 2SO4) = n * M = 1 mol * ((14 + 1 * 4) + 32 + 16 * 4) = 114 g

2. Let’s calculate the volume of ammonia, making up the proportion:

xl NH3 – 38 g (NH4) 2SO4

44.8 L NH3 – 114 g (NH4) 2SO4

Hence, x = 44.8 * 38/114 = 14.9 l

Answer: V (NH3) = 14.9 liters.

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