The nuclear icebreaker, developing a capacity of 32.4 MW, covered 20 km of ice in 5 hours.

The nuclear icebreaker, developing a capacity of 32.4 MW, covered 20 km of ice in 5 hours. Determine the average drag force of the icebreaker.

To find the value of the average force of resistance to the movement of the presented nuclear icebreaker, we use the formula: Fcopr = A / S = N * t / S.

Variables: N is the power of the specified nuclear icebreaker (N = 32.4 MW = 32.4 * 10 ^ 6 W); t is the duration of the icebreaker’s movement (t = 5 h = 18 * 10 ^ 3 s); S – distance traveled (S = 20 km = 2 * 10 ^ 4 m).

Let’s make a calculation: Fcopr = N * t / S = 32.4 * 10 ^ 6 * 18 * 10 ^ 3 / (2 * 10 ^ 4) = 29.16 * 10 ^ 6 N.

Answer: The average force of resistance to movement of the presented icebreaker is 29.16 MN.