The number of hydrogen atoms in 11 g of ammonium acetate is …

1 mol of this compound contains 4 + 3 = 7 mol of hydrogen atoms. But according to the condition of the problem, we do not know how many moles of the substance were given to us, but we can find, knowing the mass of the acetate.

Let’s calculate the number of moles of ammonium acetate.

n (NH4 (CH3COO)) = m (NH4 (CH3COO)) / M (NH4 (CH3COO)) = 11/77 = 0.14 mol

1 mol NH4 (CH3COO) – 7 mol Н

0.14 mol NH4 (CH3COO) -?

n (H) = 0.14 * 7 = 1 mol

To find the number of hydrogen atoms, multiply n (H) by the Avogadro number Na.

Na = 6.02 * 10 ^ 23

N = n (H) * Na = 6.02 * 10 ^ 23 hydrogen atoms are contained in 11 g of NH4 (CH3COO)