The number of hydrogen atoms in 4.48 liters of ammonia. What does it matter?

Given:

V (NH3) = 4.48 l.

To find:

N (H) =?.

Decision:

n (NH3) = V (NH3) / Vm;
n (NH3) = 4.48 / 22.4 = 0.2 mol.

N (NH3) = n * Na;
N (NH3) = 0.2 * 6.02 * 10 ^ 23 = 1.204 * 10 ^ 23 molecules.

N (H) = N (NH3) * 3;
N (H) = 3 * 1.204 * 10 ^ 23 = 3.612 * 10 ^ 23 atoms.

Answer: N (H) = ~ 3.6 * 10 ^ 23 atoms.



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