The obtuse angle of the parallelogram is 130 find the outer corner at the apex of the acute angle.

Since in a parallelogram the sum of the angles belonging to one side is 180, the angle BAD = 180 – ABC = 180 – 130 = 50.

The external angle KAB will be equal to: KAB = 180 – BAD = 180 – 50 = 130. The external angle of the parallelogram is equal to one of its internal corners.

Answer: The outer corner is 130.



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