The occupied volume of a certain mass of an ideal gas was reduced by 2 times, while simultaneously
| July 20, 2021 | education
The occupied volume of a certain mass of an ideal gas was reduced by 2 times, while simultaneously heating it so that the final temperature turned out to be 3 times higher than the initial one. How did the pressure change?
V2 = V1 / 2.
T2 = 3 * T1.
P2 / P1 -?
Let us use the unified gas law: for a constant gas mass, the product of the gas pressure P by its volume V divided by the temperature T remains unchanged: P * V / T = const.
P1 * V1 / T1 = P2 * V2 / T2.
P2 / P1 = V1 * T2 / V2 * T1 = 2 * V1 * 3 * T1 / V1 * T1 = 6.
Answer: gas pressure will increase 6 times: P2 / P1 = 6.
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