The OK beam passes between the sides of the angle AOB equal to 77 degrees and divides it into two angles.

| April 2, 2021 | education

The OK beam passes between the sides of the angle AOB equal to 77 degrees and divides it into two angles. Find the values of these angles if one of them is 2.5 times smaller than the other.

Let us denote by the variable x the smaller of the angles, which was formed when the AOB angle was divided by the OC beam.

Consequently, according to the condition of the problem, the larger angle that was formed when the AOB angle was divided by the OK beam, we can express in terms of 2.5x.

Knowing by the condition of the problem that the sum of the resulting angles is 77 °, we will compose an equation and determine how many degrees each of the resulting angles is equal to:

x + 2.5x = 77;

3.5x = 77;

x = 22;

2.5x = 2.5 * 22 = 55.

Answer: The smaller of the resulting angles is 22 °, the larger is 55 °.



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