The oscillating circuit consists of a capacitor with a capacity of 0.4 μF and a coil with an inductance of 200 μH.

The oscillating circuit consists of a capacitor with a capacity of 0.4 μF and a coil with an inductance of 200 μH. The capacitor was initially charged to 120V. What is the peak value of the current?

Given:
Capacitance = 0.4 μF;
inductance = 200 μH;
U = 120 V.
Find: the peak value of the current I.
Decision:
In order to find the answer, we will use the formula:
C * Um ^ 2/2 = L * Im ^ 2/2. Since we need to find the amplitude value, we express it from this formula. We then get: Im = U * root of (C / L). Let’s substitute the values of the variables into this formula and find the answer. Im = 120 * root of * 0.4 * 10 ^ -6 / 200 * 10 ^ -6) = 5.4 A.
Answer: 5, 4