The oscillating circuit consists of a capacitor with a capacity of 3 * 10-6 F and a coil with an inductance of 0.02 H.

The oscillating circuit consists of a capacitor with a capacity of 3 * 10-6 F and a coil with an inductance of 0.02 H. Determine the frequency of natural electromagnetic oscillations in this circuit.

The frequency of natural electromagnetic oscillations of the circuit depends on the capacitance of the capacitor C and the inductance of the coil L:
f = 1 / (2 * p i * root (LC))
Substitute the values from the condition:
f = 1 / (2 * 3.14 * root (3 * 10 ^ -6 F * 0.02 Hn)) = 1 / (6.28 * root (6 * 10 ^ -8)) = 650 Hz.
Answer: 650 Hz.