The oscillating circuit consists of a capacitor with a capacity of C = 10 nF and a coil with an inductance

The oscillating circuit consists of a capacitor with a capacity of C = 10 nF and a coil with an inductance of L = 190 mH. Find the period T of the natural oscillations of the circuit.

The period of free oscillations in a given oscillatory circuit is calculated using the following formula (Thompson’s formula):
T = 2 * Π * √ (L * C), where L is the given inductance of the coil (L = 190 mH = 190 * 10-3 H), C is the given electrical capacity of the capacitor (C = 10 nF = 10 * 10-9 F ).
Let’s do the calculation:
T = 2 * Π * √ (L * C) = 2 * 3.14 * √ (190 * 10-3 * 10 * 10-9) = 0.274 * 10-3 s = 0.274 ms.
Answer: The period of free oscillations in a given oscillatory circuit is 0.274 * 10-3 s or 0.274 ms.