The oscillating circuit consists of a coil with an inductance of 4 mH and a capacitor with

The oscillating circuit consists of a coil with an inductance of 4 mH and a capacitor with an electric capacity of 50 pF. Find the oscillation period in the contour.

The period of oscillation in the circuit is calculated using the Thompson formula:
T = (2 * Π * √ (L * C)), where L is the inductance of the coil (L = 4 mH = 4 * 10 ^ -3 H), C is the capacitance of the capacitor (C = 50 pF = 50 * 10 ^ – 12 F).
Let’s calculate the period of oscillation in the circuit:
T = (2 * Π * √ (L * C)) = (2 * 3.14 * √ ((4 * 10 ^ -3) * 20 * 10 ^ -12)) = (2 * 3.14 * 4 , 47 * 10 ^ -7) = 2.8 * 10 ^ -6 s.
Answer: The period of oscillation in the circuit is 2.8 * 10 ^ -6 s.



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