The oscillation frequency of the mathematical pendulum is 2.6 Hz.
The oscillation frequency of the mathematical pendulum is 2.6 Hz. What will be the oscillation frequency of the same pendulum if its length is increased by 69%?
To determine the value of the oscillation frequency of the presented pendulum, we apply the formula: νx = 1 / 2Π * √ (g / lx), whence we express: 1 / (4 * Π ^ 2) = g / (lx * νx ^ 2) and lx * νx ^ 2 = 1 / (g * 4 * Π ^ 2). Therefore, the equality will be true: l1 * ν1 ^ 2 = l2 * ν2 ^ 2 and ν ^ 2 = √ (l1 * ν1 ^ 2 / l ^ 2).
Variable values: l2 (final length of the pendulum) = 1.69l1 (initial length of the pendulum); ν1 – initial vibration frequency (ν1 = 2.6 Hz).
Calculation: ν2 = √ (l1 * ν1 ^ 2 / l ^ 2) = √ (l1 * 2.62 / 1.69l21) = 2 Hz.
Answer: After increasing the length of the presented pendulum, its oscillation frequency will be equal to 2 Hz.