The Ostankino tower, weighing 8.2 * 100000 tons, stands on a foundation on ten supports.

| March 10, 2021 | education

The Ostankino tower, weighing 8.2 * 100000 tons, stands on a foundation on ten supports. Determine the area of each of the dumps if the pressure exerted by the tower on the foundation is p 6.8 MPa.

Given:

M = 8.2 * 10 ^ 5 tons – the mass of the Ostankino tower;

n = 8 is the number of tower supports;

P = 6.8 MPa = 6,800,000 Pascal – the pressure exerted by the tower on the foundation.

It is required to determine s (m2) – the area of each support.

Let’s convert the units of measurement of mass to the SI system:

M = 8.2 * 10 ^ 5 tons = 8.2 * 10 ^ 5 * 103 = 8.2 * 108 kilograms.

Then, the total support area of the tower will be equal to:

S = F gravity / P = M * g / P = 8.2 * 10 ^ 8 * 10 / 6,800,000 = 8.2 * 10 ^ 4/68 = 82,000 / 68 = 1205.9 m2 (the result has been rounded to one decimal place) …

The area of one support will be equal to:

s = S / n = 1205.9 / 8 = 150.7 m2.

Answer: the area of one support is 150.7 m2.



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