The outer angle at the base of an isosceles triangle is 112 degrees. Find the corner of the triangle opposite the base …

So, in order to solve this problem, we need to remember the following statements:
1. The sum of all the angles of the triangle is 180 °;
2. The sum of two adjacent angles is also 180 °;
3. In an isosceles triangle, the angles at the base are equal.
Knowing the outer corner of the triangle, we can find one of the inner angles:
180 – 112 = 68 °;
Since this angle refers to the base, the second angle of the triangle is also 68 °.
Now, knowing the two angles of the triangle, we can find the third corner opposite the base to the base:
180 – 68 – 68 = 44 °;
Answer: 44 °