The outer angle at the base of an isosceles triangle is 124 degrees. Find the angle between the side
| May 2, 2021 | education
The outer angle at the base of an isosceles triangle is 124 degrees. Find the angle between the side and the median to the base of the triangle.
The external angle BAC is adjacent to the internal angle BAC, then the angle BAC = (180 – 124) = 56.
Since the triangle ABC is isosceles, the angle BCA = BAC = 56, then the angle ABC = (180 – 56 – 56) = 68.
The median BH of an isosceles triangle ABC is also its bisector, then the angle ABH = ABC / 2 = 68/2 = 34.
Answer: The angle between the lateral side and the median is 34.
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