The outer angle at the base of an isosceles triangle is 136 °. find the corners of the triangle

An isosceles triangle is a triangle in which the sides and angles at the base are equal:

∠А = ∠С.

The outer corner of a triangle is an angle adjacent to one of its corners. Since the sum of the outer and inner angles of a triangle at one vertex is equal to 180º, then:

∠А = 180º – φ;

∠А = 180º – 136º = 44º.

Since ∠А = ∠С, then:

∠С = 44º.

The sum of all the angles of the triangle is 180º, so:

∠В = 180º – ∠А – ∠С;

∠В = 180º – 44º – 44º = 92º.

Answer: angles ∠А and ∠С are equal to 44º, angle ∠В is equal to 92º.