The outer angle at the base of an isosceles triangle is 140 °. Find the corners of the triangle.
| August 4, 2021 | education
The sum of the outer and inner angles at the base of the triangle is 180 °, so the angle at the base <A = 180 ° – 140 ° = 40 °;
the angles at the base of an isosceles triangle are: <A = <B = 40 °;
angle at the apex of the triangle <C = 180 ° – 2 * 40 ° = 100 °;
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