The outer angle at the vertex B of the triangle ABC is 40 degrees, and one of the

The outer angle at the vertex B of the triangle ABC is 40 degrees, and one of the inner angles of this triangle is 20 degrees. Compare the segments AB and BC

If the outer angle at the vertex B is equal to 40˚, then the inner angle B is equal to:

180˚ – 40˚ = 140˚.

Since one angle is 140˚ and the other is 20˚, the third angle is:

180˚ – 140˚ – 20˚ = 20˚.

This means that triangle ABC is an isosceles triangle with AB = BC.

Answer: segments AB and BC are equal.



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