The outer angle of a triangle is 60 and 50 degrees greater than the angles not adjacent

The outer angle of a triangle is 60 and 50 degrees greater than the angles not adjacent to it, respectively. Is this triangle acute?

1) Let the angles a, b, and c in triangle ABC have the ratio: angle a = (a + b) – 50; angle b = (a + b) – 60, here the angle equal to (a + b) is the value of the external angle not adjacent to the angles a and b, and its value, as is known, is equal to the sum (a + b).

2) Add (a + b) = (a + b) – 50 + (a + b) – 60, whence 2 * (a + b) – (a + b) = 50 + 60; (a + b) = 110.

3) Calculate the third angle of the triangle ABC, angle c = 180 – (a + b) = 180 – 110 = 70.

4) Let’s calculate the angles a and b: a = 110 – 50 = 60; ; angle в = 110 – 60 = 50. That is, the angles of the triangle: a = 60; h = 50; c = 70; acute-angled triangle.