The outer angle of an isosceles triangle is 3 times the angle adjacent to it. Find the angles of the triangle

Let the angle BAC = X0, then the angle BAC = 3 * X0.

The sum of adjacent angles is 180, then X + 3 * X = 180.

4 * X = 180.

X = BAC = 180/4 = 45.

Then the angle BCA = BAC = 45, angle ABC = 180 – 45 – 45 = 90.

Answer: The angles of the triangle are 45, 45, 90.



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