The outer angle of the triangle is 115 degrees. and the interior angles not adjacent to it are such that one is 65

The outer angle of the triangle is 115 degrees. and the interior angles not adjacent to it are such that one is 65 degrees larger than the other. Find the corners of the triangle.

Let the outer angle at the vertex A be 115, the angle ВAK = 115.
Then the angles not adjacent to it are the angle ABC and BCA, the difference between which is equal, by condition, to 65.
Angle (ACB – ABC) = 65. (1).
The outer angle of a triangle is equal to the sum of the inner angles that are not adjacent to it.
Angle ВAK = (ABC + AСВ). (2).
Let’s solve the system of equations 1 and 2.
Angle ACB = 65 + ABC.
115 = ABC + (65 + ABC).
2 * ABC = 50.
Angle ABC = 50/2 = 25.
Then the angle ACB = 25 + 65 = 90.
Angle BAC = (180 – 90 – 25) = 65.