The outer angles at the two vertices of the triangle are 110 degrees 160 degrees. Find each corner of the triangle.
| August 5, 2021 | education
The outer corner KAB is adjacent to the inner corner BAC, triangle ABC. The sum of adjacent angles is 180, then the angle BAC = (180 – 160) = 20.
Similarly, the internal angle BCA = (180 – BCM) = (180 – 110) = 70.
Then the angle ABC = (180 – BAC – BCA) = (180 – 20 – 70) = 90.
Answer: The angles of the triangle ABC are equal to 20, 70, 90.
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