The outer corner at the apex of an isosceles triangle 142 * Find all the corners of the triangle.

1. Let the external angle of the angle C be 142 degrees, then the angle C = 180-142 = 38 degrees.
2. Angle A and angle B = (180-38) / 2 = 142/2 = 71.
Answer: A = 71, B = 71, C = 38



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