The outer corner of the triangle = 110, and the inner ones, not adjacent to it, are referred to as 5: 6.
| July 6, 2021 | education
The outer corner of the triangle = 110, and the inner ones, not adjacent to it, are referred to as 5: 6. Find the corners of the triangle.
The outer angle DAB is equal to the sum of the inner angles of the triangle ABC that are not adjacent to it.
DAB = ABC + ACB.
110 = 5 * X + 6 * X = 11 * X.
X = 110/11 = 10.
Angle ABC = 5 * 10 = 50, angle ACB = 6 * 10 = 60.
Answer: The angles of the triangle are 50, 60, 70.
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