The outside angle BCP of triangle DBC is 150 degrees, side BC = 12 cm Find the distance from point B to line DC.
| August 8, 2021 | education
The external angle HРВ and the internal angle ВСD are adjacent angles, the sum of which is 180, then the angle ВСD = 180 – HРВ = 180 – 150 = 30.
Let’s draw from the top B the height BH to the side CD.
In a right-angled triangle EH, the leg BH lies opposite the angle 30, and therefore, its length is equal to half the length of the hypotenuse of the BC.
ВН = ВС / 2 = 12/2 = 6 cm.
Answer: The distance from point B to the side of CD is 6 cm.
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