The oxidation of 1.8 g of some organic matter of the ammonia solution of silver oxide obtained 5.4 g of silver.

The oxidation of 1.8 g of some organic matter of the ammonia solution of silver oxide obtained 5.4 g of silver. What organic matter was oxidized

RCHO + Ag2O => RCOOH + 2Ag? 1 mol Ag2O – 2 mol Agn (RCHO) =? n (Ag) =? m (Ag) / M (Ag) =? 5.4 g: 108 g / mol = 0.05 / 2 = 0.025 mol M (RCHO) = m (RCHO) / n (RCHO) = 1.8 g: 0.025 mol = 72 g / mol M (R) = M (RCHO) – M (CHO) = 72 g / mol – (12 + 16 + 1) g / mol = 43 g / mol This value of M (R) corresponds to the alkyl radical C3H7. Answer. Therefore, the formula of the alkyl radical R is C3H7, and the sought substances are butyric and isobutyric acids: CH3 – CH2 – CH2 – COOH and CH3 – C (CH2) H2 – COOH