The oxidation of 92 g of toluene yielded 116 g of benzoic acid. Calculate the product yield in% of theoretical.

1. Let’s draw up a scheme of the reaction of oxidation of toluene to benzoic acid:

C6H5CH3 + [O] → C6H5COOH + H2O;

2. Let’s calculate the chemical amount of toluene:

n (C6H5CH3) = m (C6H5CH3): M (C6H5CH3);

M (C6H5CH3) = 6 * 12 + 5 + 12 + 3 = 92 g / mol;

n (C6H5CH3) = 92: 92 = 1 mol;

3. Determine the theoretical amount of benzoic acid:

ntheor (C6H5COOH) = n (C6H5CH3) = 1 mol;

4. Find the practical amount of acid obtained:

npr (C6H5COOH) = m (C6H5COOH): M (C6H5COOH);

M (C6H5COOH) = 6 * 12 + 5 + 12 + 32 + 1 = 122 g / mol;

npr (C6H5COOH) = 116: 122 = 0.9508 mol;

5. Let’s calculate the product yield:

ν = npr (C6H5COOH): ntheor (C6H5COOH) = 0.9508: 1 = 0.9508 or 95.08%.

Answer: 95.08%.