The pan has a mass of 500g. 5 liters of water are poured into it. What pressure does a pot of water

The pan has a mass of 500g. 5 liters of water are poured into it. What pressure does a pot of water exert on a gas stove if the contact area is 8 cm2.

Let’s recall the formulas for calculating the pressure that we will use:

p = F / S;

The force is calculated as:

F = mtot * g and we get the formula:

p = mtotg / S.

Let’s translate the data into the SI system and calculate the mass of water poured into the pan:

V = 5 liters = 0.005 m ^ 3;

waterways = 1,000 kg / m ^ 3.

mwater = pods * V = 1000 kg / m ^ 3 * 0.005 m ^ 3 = 5 kg.

mpans = 500 grams = 0.5 kg.

Total weight of the pot with water:

mtotal = mwater + mcast = 5 kg + 0.5 kg = 5.5 kg.

S = 8 cm ^ 2 = 0.0008 m ^ 2.

It remains to substitute the values into the formula and calculate:

p = mg / S;

p = 5.5 kg * 10 N / kg / 0.0008 m ^ 2 = 68 750 Pa.