The parachutist opened his parachute at an altitude of 1 km from the surface of the Earth

The parachutist opened his parachute at an altitude of 1 km from the surface of the Earth and then moved uniformly and in a straight line at a speed of 7 m / s vertically downward. At what distance from the Earth’s surface was it 1 min after the parachute was deployed?

Given:

L = 1 kilometer = 1000 meters – the height at which the parachutist opened the parachute;

v = 7 meters per second – the speed with which the parachutist moved after opening the parachute;

t = 1 minute = 60 seconds – time span.

It is required to determine H (meter) – at what height above the Earth’s surface was the parachutist after a time interval t.

In time t, the parachutist will fly a distance equal to:

L1 = v * t = 7 * 60 = 420 meters.

Then the height can be determined from the following ratio:

H = L – L1 = 1000 – 420 = 580 meters.

Answer: in 1 minute the parachutist will be at an altitude of 580 meters above the Earth’s surface.