The parachutist opened the parachute at a height of 2 km above the ground, began to move straight

The parachutist opened the parachute at a height of 2 km above the ground, began to move straight and evenly at a speed of 18 km / h. How long will it take to land?

Initial data: h (altitude at which the parachutist opened his parachute) = 2 km (2000 m); after opening the parachute, the movement of the parachutist is rectilinear and uniform and V (speed of the parachutist) = const = 18 km / h (5 m / s).

The duration of the descent of the parachutist is determined by the formula: t = S / V.

Calculation: t = 2000/5 = 400 s (6 min 40 s).

Answer: The skydiver will land in 6 minutes 40 seconds.



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