The parallelogram angle is 60 degrees, the smaller diagonal is 7cm
The parallelogram angle is 60 degrees, the smaller diagonal is 7cm, and one of the sides is 5cm. Find the area and perimeter of the parallelogram.
From the top B let us lower the height BH to the base of AD.
In a right-angled triangle ABН, the angle ABН = 180 – 60 = 30, then the leg AH is equal to half the length of the hypotenuse AB. AH = 5/2 = 2.5 cm.
Then the height of BH, according to the Pythagorean theorem, will be equal to: BH ^ 2 = AB ^ 2 – AH ^ 2 = 25 – 6.25 = 18.75.
From the right-angled triangles НВD, according to the Pythagorean theorem, determine the length of the leg НD.
HD ^ 2 = BD ^ 2 – BH ^ 2 = 49 – 18.75 = 30.25.
НD = √30.25 = 5.5 cm.
Then the side AD = AH + HD = 2.5 + 5.5 = 8 cm.
Determine the perimeter of the parallelogram.
P = 2 * (AB + AD) = 2 * (5 + 8) = 26 cm.
Determine the area of the parallelogram.
S = AD * BH = 8 * √18.75 = 34.6 cm2.
Answer: The perimeter is 26 cm, the area is 34.6 cm2.