The passenger walked for half an hour to the bus stop, and then drove 40 minutes to work.

The passenger walked for half an hour to the bus stop, and then drove 40 minutes to work. How many times is the driving speed greater than the walking speed if the passenger has traveled 10 times the distance than he has traveled?

Initial data: t1 (time of passenger movement before stopping) = 30 min; t2 (travel time of a passenger on the bus) = 40 min; S2 (distance traveled by the bus) = 10S1 (distance traveled to stop).

Passenger walking speed: V1 = S1 / t1 = S1 / 30.

Bus speed: V2 = S2 / t2 = 10S1 / 40.

Velocity ratio: V2 / V1 = (10S1 / 40) / (S1 / 30) = 10S1 * 30 / (S1 * 40) = 300/40 = 7.5 p.

Answer: The speed of a passenger on a bus is 7.5 times higher.