The path traversed by the body in the 2nd second s = 6.5m. The initial velocity
| June 23, 2021 | education
The path traversed by the body in the 2nd second s = 6.5m. The initial velocity of the body is v0 = 2m.s. Find the acceleration of the body (the body is moving uniformly).
Problem data: S (2) – the path traversed by the given body in the 2nd second (S (2) = 6.5 m); V0 – initial speed (V0 = 2 m / s).
To determine the constant acceleration of a given body, we apply the formula: S (2) = S2 – S1 = V0 * t ^ 2 + 0.5 * a * t2 ^ 2 – V0 * t1 – 0.5 * a * t1 ^ 2.
Substitute the known values: 6.5 = 2 * 2 + 0.5 * a * 2 ^ 2 – 2 * 1 – 0.5 * a * 1 ^ 2.
6.5 = 4 + 2 * a – 2 – 0.5 * a.
4.5 = 1.5a.
a = 4.5 / 1.5 = 3 m / s2.
Answer: The constant acceleration of a given body is 3 m / s2.
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