The pedestrian moves at a uniform speed and covered a distance of 12 meters

The pedestrian moves at a uniform speed and covered a distance of 12 meters in 6 seconds. How far will he travel at the same speed in 3 seconds?

t1 = 6 s.

S1 = 12 m.

t2 = 3 s.

S2 -?

With uniform rectilinear movement, the speed of movement V is determined by the ratio of the distance traveled S to the time of its passage t: V = S / t.

Let’s find the speed of the pedestrian: V = S1 / t1.

V = 12 m / 6 s = 2 m / s.

The distance S2 passed by it will be the product of the speed of movement V and the time of movement t2: S2 = V * t2.

S2 = 2 m / s * 3 s = 6 m.

Answer: the pedestrian will cover the distance S2 = 6 m during the movement t2 = 3 s.