The pendulum on Earth has an oscillation period of 1 s. What will be its period of oscillation on the Moon

The pendulum on Earth has an oscillation period of 1 s. What will be its period of oscillation on the Moon (where gl = l, 6 m / s2)?

Initial data: Tz (period of oscillation of the pendulum on Earth) = 1 s.

Reference values: gz (acceleration of gravity at the Earth’s surface) = 10 m / s2; by the condition gл (acceleration of gravity on the surface of the Moon) = 1.6 m / s2.

1) Pendulum length: Tz = 2Π * √ (l / gz); l / gz = Tz ^ 2 / 4Π ^ 2 and l = Tz ^ 2 * gz / 4Π ^ 2 = 12 * 10 / (4 * 3.14 ^ 2) = 0.254 m.

2) The period of oscillation of the pendulum on the Moon: T = 2Π * √ (l / gl) = 2 * 3.14 * √ (0.254 / 1.6) = 2.5 s.

Answer: The period of oscillation of the pendulum on the moon is 2.5 s.