The percentage composition of the compound, the following Cl-89.9%, C-10.1% Determine its molecular formula.

Let’s implement the solution, write down the data on the condition of the problem:
1. Given: W (Cl) = 89, 9%
Ar (Cl) = 35.5;
Ar (C) = 12;
W (C) = 10.1%
Determine: molecular formula.
2. Calculations:
Y (Cl) = 89.9 / 35.5 = 2.53 mol;
Y (C) = 10.1 / 12 = 0.84 mol.
3. Ratio:
С: Сl = X: Y = 0.84: 2.53 = 1: 3 (divide by the smallest number);
CCl3 – radical;
CHCl3 is a formula.
Answer: chloroform – CHCl3.