The perimeter of a 60-degree rhombus is 60 cm. Find its smaller diagonal.

We have a rhombus, the perimeter of which is 60 cm, and the apex angle is 60 °.

A rhombus is a parallelogram in which all sides are equal. Find the length of one side:

a = P / 4 = 60/4 = 15 cm.

The smaller diagonal of the rhombus divides it into two equal isosceles triangles. In our problem, it is known that in these triangles the angle between the sides in the triangle is 60 °, respectively, all the angles of the triangle are 60 °, and the triangle becomes equilateral.

One of the sides of such a triangle is just the smaller diagonal of the rhombus, respectively, its length is 25 cm.