The perimeter of a rectangle is 24dm; its width is 4dm less than its length. What is the area of the rectangle?

We will solve this problem by drawing up an equation;

Let x dm be the value of the width of the given rectangle;

Then x + 4 dm is the value of the length of this rectangle;

We also know that the value of the perimeter of this rectangle is 24 dm, we draw up an equation of the following form:

2 * (x + x + 4) = 24;

x + x + 4 = 24: 2;

x + x + 4 = 12;

2 * x = 12 – 4;

2 * x = 8;

x = 8: 2;

x = 4.

4 dm is the value of the width of this rectangle;

4 + 4 = 8 dm – the value of the length of this rectangle;

Let’s find the value of the area of ​​this rectangle, for this, the value of the width of this rectangle is multiplied by the value of the length of this rectangle:

4 * 8 = 32 dm2 – the value of the area of ​​this rectangle.

Answer: 32 dm2 is the value of the area of ​​this rectangle.