The perimeter of a rectangle is 48 inches. Its width is 1/2 of its length. Find the lengths of the sides of this rectangle.

1. Let’s say that the length of the given rectangle is x dm.

2. Since according to the condition of the problem, the width of this rectangle is 1/2 of t of its length, therefore it will be equal to (1/2 * x) = x / 2 dm.

3. Since we know that the perimeter of a given rectangle is 48 dm, we make an equation and find out what the length of this rectangle is.

x + x + x / 2 + x / 2 = 48;

2x + 2x + x + x = 96;

6x = 96;

x = 96/6;

x = 16 dm.

4. Find out what the width of the rectangle is.

16/2 = 8 dm.

Answer: The length of the rectangle is 16 dm, the width is 8 dm.