The perimeter of a rectangle is 48dm, its width is 1/2 of its length, find the lengths of the sides of this rectangle.

1. If we imagine that the length is x, then the width will be x / 2. Let’s compose an equation based on the formula for the perimeter of a rectangle P = 2a + 2b, where P is the perimeter, width a and length b:

2 * x + 2 * x / 2 = 48,

2 * x + x = 48,

3 * x = 48,

x = 48/3,

x = 16.

2. Determine what the width is equal to:

16 dm / 2 = 8 dm.

Answer: The rectangle is 8 inches wide and 16 inches long.