The perimeter of a square circumscribed about a circle is 6 cm larger

The perimeter of a square circumscribed about a circle is 6 cm larger than the perimeter of a pentagon inscribed in the same circle. Find the radius of this circle.

The perimeter of the square is equal to: Ravsd = 4 * AB.

The radius of the inscribed circle in the square is equal to half the length of its side, then Ravsd = 4 * 2 * R = 8 * R cm.

Since a regular pentagon is inscribed in a circle, the length of its side is:

KН = 2 * R * Sin (180/5) = 2 * R * Sin36.

Then P5 = 5 * 2 * R * Sin36 = 10 * R * Sin36.

By condition, Ravsd – P5 = 6 cm.

8 * R – 10 * R * Sin36 = 6.

R * (8 – 10 * Sin36) = 6.

R = 6 / (8 – 10 * Sin36) cm

Answer: The radius of the circle is 6 / (8 – 10 * Sin36) cm.



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