The perimeter of a square is 28 cm. How many centimeters can be the length and width of a rectangle whose perimeter is equal to the perimeter of the square?
By the condition of the problem, the perimeter of the rectangle is 28 cm.Thus, the doubled sum of the two sides of the rectangle is 28 cm.Let’s find the sum of the two sides of the rectangle, dividing the known perimeter by 2:
28: 2 = 14 (cm).
Thus, the sum of the length and width of the rectangle is 14 cm.
Let’s select the possible options for the lengths of the sides of the rectangle:
8 cm and 6 cm (8 + 6 = 14),
9 cm and 5 cm (9 + 5 = 14),
11 cm and 3 cm (11 + 3 = 14),
10 cm and 4 cm (10 + 4 = 14),
12 cm and 2 cm (12 + 2 = 14),
13 cm and 1 cm (13 + 1 = 14).
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