The perimeter of a triangle ABC is 15.5 cm Find the lengths of the sides of this triangle if AB
August 22, 2021 | education
| The perimeter of a triangle ABC is 15.5 cm Find the lengths of the sides of this triangle if AB refers to BC as 3: 5 and BC refers to AC as 2: 3
1. Let X cm be the length of one part.
It is known that AB refers to BC as 3: 5.
Then the length of AB is (3 * X) cm.
BC length is (5 * X) cm.
2. At the same time BC refers to AC as 2: 3.
AC length is (5 * X) / 2 * 3 = (15/2 * X) cm.
3. By the statement of the problem, the perimeter of triangle ABC is 15.5 cm.
We got the equation.
3 * X + 5 * X + 15/2 * X = 15.5.
16/2 * X + 15/2 * X = 15.5.
X * 15.5 = 15.5.
X = 1 cm.
4. Then AB = 3 * 1 = 3 cm.
BC = 5 * 1 = 5 cm.
AC = 15/2 * 1 = 7.5 cm.
Answer: the lengths of the sides of the triangle are 3 cm, 5 cm and 7.5 cm.
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