# The perimeter of a triangle is 62 cm, find the lengths of its sides if one of them is 2 times

**The perimeter of a triangle is 62 cm, find the lengths of its sides if one of them is 2 times longer than the second, and the third is 8 cm**

To find the lengths of the sides of a triangle, we will compose and solve the equation using the equation, based on the formula for finding the perimeter of the triangle.

P = a + b + c;

From the condition, we know that the perimeter is 62 cm. It is also known that one of the sides is 2 times longer than the second, and the third by 8 cm. Let’s denote the length of one of the sides by x cm. Then we write the second as x / 2 cm, and the length of the thirds (x – 8) cm.

We get the equation:

x + x / 2 + (x – 8) = 62;

2x + x + 2 (x – 8) = 124;

2x + x + 2x – 16 = 124;

5x = 124 + 16;

5x = 140;

x = 28 cm length of one side, 28/2 = 14 cm, 28 – 8 = 20 cm side of the triangle.