The perimeter of an equilateral triangle is 110 cm. If the ratio of the two walls is 3: 4, what can the walls of the triangle be?

Let’s designate a triangle ABC, AB = BC.

1. Let AB be 3x, then BC will be 3x, and AC will be 4x.

Let’s get an equation based on the fact that the perimeter is equal to the sum of all sides:

3x + 3x + 4x = 110;

10x = 110;

x = 11.

Then AB and BC will be:

3 * 11 = 33 cm.

AC is equal to:

4 * 11 = 44 cm.

Answer: AB = BC = 33 cm, AC = 44 cm.

2. If we assume that AB = BC = 4x, then AC = 3x.

We get the following equation:

4x + 4x + 3x = 110;

11x = 110;

x. = 10.

Find AB and BC:

4 * 10 = 40 cm.

Let’s find the AC:

3 * 10 = 30 cm.

Answer: AB = BC = 40 cm, AC = 30 cm.