The perimeter of an isosceles obtuse angle is 77 cm, and one of its sides is 17 cm larger than the other.

The perimeter of an isosceles obtuse angle is 77 cm, and one of its sides is 17 cm larger than the other. Find the sides of this triangle.

From the condition, we know that the perimeter of an isosceles triangle is 77 cm, and one of its sides is 17 cm larger than the other.

In order to find the sides of a triangle, we compose and solve a linear equation with one variable.

we denote by the variable x the length of one of the sides, then the length of the second can be written as (x + 17).

Perimeter of an isosceles triangle: P = 2a + b.

Let the side be equal to x cm, then we get the equation:

2x + x + 17 = 77;

3x = 60;

x = 20 cm lateral side, 37 cm – base of the triangle.

Answer: 20 cm; 20 cm; 37 cm.