The perimeter of an isosceles obtuse triangle = 77cm, and one of its sides is 17cm larger than the other.

The perimeter of an isosceles obtuse triangle = 77cm, and one of its sides is 17cm larger than the other. find the sides of this triangle.

From the condition it is known that the perimeter of an isosceles obtuse triangle is 77 cm, and one of its sides is 17 cm larger than the other. In order to find the sides of this triangle, we compose and solve the equation.

The condition says that the triangle is obtuse, which means that a large side lies opposite the obtuse angle.

We denote by the variable x cm the side (there are two of them and they are equal to each other), then the base is (x + 17) cm.

Perimeter is the sum of the lengths of all sides.

2x + x + 17 = 77;

3x = 77 – 17;

3x = 60;

x = 20 cm side, 20 + 17 = 37 cm base of the triangle.