The perimeter of an isosceles obtuse triangle is 108 m. One of the sides of this triangle

The perimeter of an isosceles obtuse triangle is 108 m. One of the sides of this triangle is 9 m larger than the other. Find the sides of the triangle.

1. A, B, C – the vertices of the triangle.

2. According to the condition of the problem, the AC is more than AB by 9 meters. Therefore, AC = AB + 9.

3. Further calculations are performed using the formula for calculating the perimeter

triangle:

AC + AB + BC = 108 meters.

BC = AB, since this triangle is isosceles.

4. Substitute AB instead of BC and (AB + 9) instead of AC into the original formula:

AB + 9 + 2AB = 108.

3AB = 99.

AB = 99: 3 = 33 meters.

AC = 33 + 9 = 42 meters.

Answer: AC = 42 meters, AB = BC = 33 meters.