# The perimeter of an isosceles obtuse triangle is 108 m. One of the sides of this triangle

January 28, 2021 | education

| **The perimeter of an isosceles obtuse triangle is 108 m. One of the sides of this triangle is 9 m larger than the other. Find the sides of the triangle.**

1. A, B, C – the vertices of the triangle.

2. According to the condition of the problem, the AC is more than AB by 9 meters. Therefore, AC = AB + 9.

3. Further calculations are performed using the formula for calculating the perimeter

triangle:

AC + AB + BC = 108 meters.

BC = AB, since this triangle is isosceles.

4. Substitute AB instead of BC and (AB + 9) instead of AC into the original formula:

AB + 9 + 2AB = 108.

3AB = 99.

AB = 99: 3 = 33 meters.

AC = 33 + 9 = 42 meters.

Answer: AC = 42 meters, AB = BC = 33 meters.

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